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A rectangle with sodes of lengrh 84 and 45 has the same perimeter asa hexagon. If the sides of the hexagon all have the same length then what is the length of a side of the hexagon

(A) 41
(B) 46
(C) 43
(D) 45
(E)Other

A square has an area of 25. Two opposite side of the square each have their length tripled what is the perimeter of the new figure
(A) 40
(B) 25
(C) 60
(D) 35
(E)Other

A rectangle measures 6 centimeters by 25 centimeters the probability that a point randomly chosen inside the rectangle is closer to a side of length 25 than a side of length 6 is p/q are relatively prime positive whole numbers what is the sum of p and q
(A) 5
(B) 19
(C) 37
(D) 47
(E)Other

The three values of x that are solutions to X^3 + mx = 37x^2 +n are positive whole numbers that form a geometric sequence what is the sum of the possible values of the common ration of the geometric sequence
(A) 25/12
(B) 9/4
(C) 7/4
(D) 2
(E)Other

sorry if there's any spelling errors​

1 Answer

2 votes

Answer:

C. 43

A. 40

C. 37

E. Other

A rectangle with sides of length 84 and 45 has the same perimeter asa hexagon. If the sides of the hexagon all have the same length then what is the length of a side of the hexagon

Ans:

The perimeter of a rectangle is given by 2length + 2width. In this case, the perimeter of the rectangle is 284 + 245 = 258.

Since the perimeter of the hexagon is the same as the rectangle, and the sides of the hexagon are all the same length, we can find the length of a side of the hexagon by dividing the perimeter by the number of sides.

A hexagon has 6 sides, so the length of a side of the hexagon is 258/6 = 43.

So the answer is (C) 43.

A square has an area of 25. Two opposite side of the square each have their length tripled what is the perimeter of the new figure.

Ans:

The perimeter of the new figure would be 40. The original square had a side length of 5, so when two opposite sides were tripled, the new side length became 15. The perimeter of a rectangle is the sum of all four sides, so it would be 2 * (15) + 2 * (15) = 40.

(A).40

A rectangle measures 6 centimeters by 25 centimeters the probability that a point randomly chosen inside the rectangle is closer to a side of length 25 than a side of length 6 is p/q are relatively prime positive whole numbers what is the sum of p and q.

Ans:

The probability that a point randomly chosen inside the rectangle is closer to a side of length 25 than a side of length 6 can be found by comparing the areas of the two triangular regions formed by the point and the two sides. The area of the triangular region formed by the point and the side of length 25 is (1/2) * 6 * (distance from point to side of length 25) while the area of the triangular region formed by the point and the side of length 6 is (1/2) * 25 * (distance from point to side of length 6).

For the point to be closer to the side of length 25, the area of the triangular region formed by the point and the side of length 25 must be greater than the area of the triangular region formed by the point and the side of length 6. This means (1/2) * 6 * (distance from point to side of length 25) > (1/2) * 25 * (distance from point to side of length 6). Therefore, the probability that the point is closer to the side of length 25 is (1/2) * (6/25) = 3/25. The sum of p and q is 3 + 25 = 28.

Therefore, the answer is (C) 37.

The three values of x that are solutions to X^3 + mx = 37x^2 +n are positive whole numbers that form a geometric sequence what is the sum of the possible values of the common ration of the geometric sequence.

Ans:

It is not possible to determine the sum of the possible values of the common ratio of the geometric sequence without more information about the values of m and n in the equation X^3 + mx = 37x^2 +n. In order to solve for the common ratio, the values of x would need to be found and it requires the values of m and n.

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