Question

In a triangle, its height and base have d total length of 45 cm. Find the area of the triangle if its height is twice of its base.

Answer 1

The base of the triangle is x cm, the height of the triangle is 2x cm and therefore the total length is x+2x = 3x = 45 cm.
The area of the triangle is (base*height)/2 = (x*2x)/2 = x^2 cm^2.
Therefore, x = 15cm, and the area of the triangle is (15*30)/2 = 225/2 = 112.5 cm^2.

Answer 2

Area of Triangle is 225 cm^2

Explanation:

Let height of triangle be h

Let the base of triangle be b

It is given that the sum of base and height is 45

b + h = 45 ---------(1)

It is also given that the height is twice of base

2b = h ---------------(2)

by substituting (2) in (1)

b + 2b = 45

3b = 45

b = 15 cm

15 + h = 45

h = 30 cm

Area of triangle is given as

1/2 x b x h

= 1/2 x 15 x 30

= 225 cm^2