Answer:
Pb(NO₃)₂(aq) + 2NaCl(aq) → PbCl₂(s)↓ + 2NaNO₃(aq)
Step-by-step explanation:
The precipitate formed is PbCl₂, which contains lead in it∴ Pb(NO₃)₂(aq) + 2NaCl(aq) → PbCl₂(s)↓ + 2NaNO₃(aq)
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