Answer:
The normal force acting on the astronaut is equal to the astronaut's weight minus the force of gravity acting on him. The force of gravity acting on the astronaut is equal to his mass times the acceleration due to gravity on Earth (9.8 m/s^2).
F_norm = F_gravity - ma = (89.4 kg)(9.8 m/s^2) - (89.4 kg)(47.2 m/s^2) = -4095.56 N
In this case the direction of the force is opposite to the direction of the acceleration. So the force is acting in -y direction. So the answer is -4095.56 N.