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An arrow is shot with an angle of elevation of 20°. When the arrow reaches an altitude of 482 feet, how far has the arrow flown through the air? Round
your answer to the nearest whole foot.
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figuro holow. To the nearest tenth of a foot

1 Answer

1 vote

Answer:

1409.3

Explanation:

Let the distance flown by the arrow in feet be
d.


\sin 20^(\circ)=(482)/(d) \\ \\ (1)/(\sin 20^(\circ))=(d)/(482) \\ \\ d=(482)/(\sin 20^(\circ)) \\ \\ d \approx 1409.3

User Denis Ivanov
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