Find all real solutions to x^2 - 12x + 40 = 0

asked Jul 19, 2024 46.0k views

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Answer:

No real solutions

Explanation:

$x^2-12x+40=0 \\ \\ x^2-12x=-40 \\ \\ x^2-12x+36=-4 \\ \\ (x-6)^2=-4$

By the trivial inequality, there are no real solutions.

Chiborg answered Jul 23, 2024

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