Answer:
Step-by-step explanation:
2 K + 1 Br₂ ⇒ 2 KBr
Use the balanced equation and the molar mass of KBr to find grams of KBr formed from 3.50 moles of Br₂.
Note that all units cancel except grams of KBr, which is what is being asked.
3.50 mol Br₂ x (2 mol KBr/1 mol Br₂) x (119.00 g KBr/1 mol KBr) = 833 g KBr