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The angle bisectors of AABC are AV, B, and CV. They meet at a single point V. (In other words, V is the incenter of AABC.) Suppose SV = 12, CV= 15, m L SBT=92°, and m ZUAV= 24° …
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The angle bisectors of AABC are AV, B, and CV. They meet at a single point V. (In other words, V is the incenter of AABC.) Suppose SV = 12, CV= 15, m L SBT=92°, and m ZUAV= 24° …
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Dec 25, 2024
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The angle bisectors of AABC are AV, B, and CV. They meet at a single point V.
(In other words, V is the incenter of AABC.)
Suppose SV = 12, CV= 15, m L SBT=92°, and m ZUAV= 24°
Find the following measures.
Note that the figure is not drawn to scale.
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Lakmi
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Answer:
m ZUAV = 24°
m L SBT = 92°
m L SAV = m L SBT / 2 = 92° / 2 = 46°
m L CAV = 180° - m L SAV - m ZUAV = 180° - 46° - 24° = 110°
m L SCV = m L CAV = 110°
m L SVB = 180° - m L SAV - m L SCV = 180° - 46° - 110° = 24°
m L CVB = 180° - m L CAV - m L SVB = 180° - 110° - 24° = 46°
m L SVT = 180° - m L SBT = 180° - 92° = 88°
To find the area of the triangle
Area = (1/2) x (12)(15)sin(92)
Rpbaltazar
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Dec 31, 2024
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