Question

Help what's we Have : (x, y,z) = (1, 2, 3) ; (3,2,1); (1,3,2) ; (2,1,3) ; (2,3,1), and (3,1,2)

For k= 43 we have (x,y,z) = (2,2,3) or (2,3,2) or (3,2,2)

For k = 44 we have ( 8,-7,-5) or (8,-5,-7) or (-5,-7,8) or ( -5,8,-7) or (-7,-5,8) or (-7,8,-5)

For k =54 => (x,y,z) = (13,-11,-7) ,

for k = 55 => (x,y,z) = (1,3,3) or (3,1,3) or (3,1,1)

and (x,y,z) = (10,-9,-6) or (10,-6,-9) or ( -6,10,-9) or (-6,-9,10) or (-9,10,-6) or (-9,-6,10)

For k = 62 => (x,y,z) = (3,3,2) or (2,3,3) or (3,2,3)

For k =64 => (x,y,z) = (0,0,4) or (0,4,0)

Answer 1

For k = 43, the possible values of (x,y,z) are (2,2,3), (2,3,2), and (3,2,2). For k = 44, the possible values of (x,y,z) are (8,-7,-5), (8,-5,-7), (-5,-7,8), (-5,8,-7), (-7,-5,8), and (-7,8,-5). For k = 54, the possible values of (x,y,z) are (13,-11,-7). For k = 55, the possible values of (x,y,z) are (1,3,3), (3,1,3), (3,3,1), and (1,3,1). For k = 62, the possible values of (x,y,z) are (3,3,2), (2,3,3), and (3,2,3). For k = 64, the possible values of (x,y,z) are (0,0,4) and (0,4,0).