Answer:
Q 1 : Solution:
Let the height of the building be h.
We know that tan(60) = h/9 (angle of elevation formula)
h = 9tan(60) = 9sqrt(3)/3 = 3*sqrt(3) = 3.464101615 m (approx)
Q 2 : Solution:
Let the height of the pole be h.
Let the shorter segment be x, and the longer segment be 9x.
We know that tan(theta) = x/(20) = 9x/(20+h) (angle subtended formula)
By cross multiplying and simplifying, we get:
x = (20h)/(h+180)
The ratio of the segments is x:9x = 1:9, so x = (20h)/(h+180) = 1/10 * h
h = 10x = (20h)/(h+180)
h^2 + 180h - 20h^2 = 0
h(20-h) = 0
h = 0 or h = 20
Since the pole has a height, h = 20m is not possible, so the height of the pole is h = 178.8m