Question

Solve each equation using the quadratic formula. 6x-5=-x^2

Answer 1

`x = -3 \frac{ + }{} √(14)`

Explanation:

`6x - 5 = {-x}^(2)`

`{x}^(2) + 6x - 5 = 0`

a = 1, b = 6, c= -5

`x = \frac{ - b \frac{ + }{} \sqrt{(b) {}^(2) - 4(a)(c)} }{2(a)}`

Substitute then solve

`x = \frac{ - 6 \frac{ + }{} \sqrt{( 6) {}^(2) - 4(1)(-5) } }{2(1)}`

`x = \frac{-6 \frac{ + }{} √(36 + 20) }{2}`

`x = \frac{ -6 \frac{ + }{} √(56) }{2}`

`x = \frac{ -6 \frac{ + }{}2 √(14) }{2}`

`x = -3 \frac{ + }{} √(14)`

Answer 2

Explanation:

get the standard equation ,and use the formula solve it