196k views
3 votes
An electric heater rated at 50 watts is used to

heat 100g of water in a calorimeter from 50°C to 100°C.
Calculate the time for which the current flowed. Neglect the
specific heat capacity of the calorimeter. Take the specific
heat capacity of water as 4200J/kgK.

1 Answer

3 votes

Answer:

420

Step-by-step explanation:

Heat required(Q)= m*c*

So Q=21000J

Power=50Wt

time= Q/Power

time=21000/50 sec

time=420seconds

User Efsandino
by
7.9k points