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T varies s/t when
S =36, t =16, T=18
Find T when s=33, t=18​

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Answer:

Explanation:

We are given that T varies as the square root of the ratio of s and t, and we are trying to find the value of T when s=33 and t=18.

The relationship between T, s and t can be represented by the following equation:

T = k * √(s/t)

Where k is a constant.

We are given that when S=36, t=16, T=18. We can use this information to find the value of k.

We know that T = k * √(s/t)

and, T = 18 when s=36, t=16.

So we can substitute these values in the equation

18 = k * √(36/16)

Solving for k, we get:

k = 18/2 = 9

Now that we know the value of k, we can use it to find the value of T when s=33 and t=18.

T = k * √(s/t) = 9 * √(33/18) = 9 * √(11/6) = 9 * √(11/6)

The value of T when s=33, t=18 is 9 * √(11/6),

It is not possible to give the exact value of T because the value of the square root of (11/6) is not a whole number.

User Andreas Sauer
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