Question

A body moves 5m in 3rd second and it moves 9m in the 7th second. Find the distance moved by the body between t = 5s and t = 8s.

tysm! :)​

Answer 1

34 m

Step-by-step explanation:

I will assume the body is accelerating uniformly

accel = change in velocity/change in time

4 m/s / 4 s =1 m/s^2

So in second 4 it moves 6 Then for second 5 it moves 7 m then 8 m Then 9 m in second 7 Then 10 m in second 8

Total(5 thru 8) = 34m