Question

A 3 kg ball is moving at 2.0 m/s to the right. It runs into a 1 kg ball moving at 0.5 m/s to the left. The balls bounce off each other.

Q. If the 3 kg ball moves at 1 m/s to the left after the collision, how fast must the 1 kg ball be going after the collision? Show the equation and work

Answer 1

3.5

Step-by-step explanation:

we have an equation:

m1u1+m2u2=m1v1+m2v2 where, m=mass

v=final velocity

u=intial velocity

then this means:

v2=m1u1+m2u2-m1v1÷m2

when we substitute on the equation:

v2=3×2.0+1×0.5-3×1÷1

=6+0.5-3

=6.5-3

=3.5

Answer 2

The Answer Is O.5 m/s

Step-by-step explanation:

we have an equation:

m1u1 + m2u2=m1v1 + m2v2

(u is for before collison and v is for after collision)

rearrange,

m1u1 + m2u2 - m1v1 ÷ m2 = v2

Put values and answer will be 0.5m/s