Question

Solve the equation
( attached an image of the problem)

Answer 1

B

Explanation:

`x = (2)/(3)\pi r^(3)`

The objective is to isolate r and make r the subject of the equation:

Cross-multiplication is applied:

`= 2\pi r^(3)= 3x`

The variables and number multiplied with
`r^(3)` are transferred to the other side of the equation:

`= \pi r^(3) = (3x)/(2)`

`= r^(3) = (3x)/(2\pi)`

Cube root is applied to both sides of the equation to get rid of the cube:

`= \sqrt[3]{r^(3)} = \sqrt[3]{(3x)/(2\pi)}`

`r = \sqrt[3]{(3x)/(2\pi)}`