Question

Please help me with this and explain plss

Answer 1

x = -6 and y = -8

Explanation:

These two simultaneous linear equations using elimination method:

For this method to be applied, the coefficients of ‘x’ or ‘y’ in the two equations need to be the same with opposite signs.

The coefficients of ‘x’ will be focused on:

(3x - 2y = -2) Multiplied by 7

(-7x + 6y = -6) Multiplied by 3

21x - 14y = -14

-21x + 18y = -18

In the net total, it can be observed that the two ‘x’ terms will completely cancel each other out:
4y = -32

`y = -(32)/(4)`

y = -8

Substitute this value of y in any of the equations to determine the value of x:

3x - 2(-8) = -2

3x + 16 = -2

3x = -2 - 16

3x = -18

`= x =- (18)/(3)`

x = -6

Answer 2

Answer: x=-6 y=-8

Explanation:

For 1st equation solve for x.

3x-2y=-2

3x=-2+2y

x=
`(-2+2y)/(3)`

Then plug in the x found in 1st equation into the 2nd equation.

-7x+6y=-6

-7
`((-2+2y)/(3))`+6y=-6

`(14-14y)/(3)`+6y=-6

`(14)/(3)` -
`(14y)/(3)` +6y=-6

`(4y)/(3)`=-6-
`(14)/(3)`

`(4y)/(3)`=
`(-32)/(3)`

4y=-32

y=-8

Then plug in the y value found in the 2nd equation into the 1st equation.

x=
`(-2+2y)/(3)`

x=
`(-2+2(-8))/(3)`

x=
`(-2-16)/(3)`

x=
`(-18)/(3)`

x=-6