Question

Find the equation of a line passing through the point of intersection of lines 2X plus 3Y equals to one and X minus Y +2 equals to zero and parallel to the line joining the points two, three and four, five.

Answer 1

y=2x+9

Explanation:

Point of intersection of y=3 & x+y=0

Point of intersection of y=3 & x+y=0put x=3 in x+y=0

Point of intersection of y=3 & x+y=0put x=3 in x+y=0x=−3

Point of intersection of y=3 & x+y=0put x=3 in x+y=0x=−3so the point is (−3,3)

Point of intersection of y=3 & x+y=0put x=3 in x+y=0x=−3so the point is (−3,3)2x−y=4

Point of intersection of y=3 & x+y=0put x=3 in x+y=0x=−3so the point is (−3,3)2x−y=4m=2

Point of intersection of y=3 & x+y=0put x=3 in x+y=0x=−3so the point is (−3,3)2x−y=4m=2y−3=2[x+3]

Point of intersection of y=3 & x+y=0put x=3 in x+y=0x=−3so the point is (−3,3)2x−y=4m=2y−3=2[x+3]y=2x+6+3

y=2x+9