Question

Y = x² +1,x>0
find the inverse

Answer 1

The inverse of x² +1 is:

`√(x-1),\:-√(x-1)`

Explanation:

Given

y = x² + 1, x>0

We know that A function g is the inverse of a function f if for y = f(x), x = g(y)

y = x² +1

Replace x with y

x = y² + 1

solve for y

y² = x - 1

Taking square root

`y=\:√(x-1),-√(x-1)`

Thus, the inverse of x² +1 is:

`√(x-1),\:-√(x-1)`