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what is the current that will flow through a 10k potentiometer being used as a voltage divider with a 5v input?

User Detra
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1 Answer

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Step-by-step explanation:

The current flowing through a potentiometer used as a voltage divider is given by:

I = V / R

where:

I = current (A)

V = voltage across the potentiometer (V)

R = resistance of the potentiometer (Ω)

Since a potentiometer is a variable resistor, the voltage across it, V, can be determined by the position of the wiper on the resistive element and the input voltage.

Let's assume the wiper is positioned to divide the voltage in half, so the voltage across the potentiometer is V = 5V / 2 = 2.5V.

The resistance of the 10k potentiometer can be taken as its maximum resistance, R = 10 kΩ = 10,000 Ω.

Plugging in the values:

I = 2.5V / 10,000Ω = 0.25 mA

So the current flowing through the 10k potentiometer when used as a voltage divider with a 5V input is 0.25 mA.

User Jan Kotek
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