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how many moles of gas are in a 60.8 l container with a pressure of 2.44 atm at a temperature of 275 k?

User Vulcan
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1 Answer

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Answer: 24.7 moles of gas

Step-by-step explanation:

The number of moles of gas in a container can be determined using the Ideal Gas Law, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvins.

We know that:

V = 60.8 L

P = 2.44 atm

T = 275 K

R = 0.0821 L·atm/mol·K

We can rearrange the Ideal Gas Law to solve for n:

n = PV/RT

We can substitute in the given values to find the number of moles of gas:

n = (2.44 atm)(60.8 L) / (0.0821 L·atm/mol·K)(275 K)

n = (2.44)(60.8) / (0.0821)(275)

n = approx. 24.7 mol

Therefore, there are approximately 24.7 moles of gas in the container at the given temperature and pressure.

User Touki
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