Question

Suppose a 2.5um wide slit produces its first minimum for 405nm light. A) Calculate the angle at which this occurs for the 405nm light in degrees. B) where is the first minimum in degrees for 740nm light?

Answer 1

A) To calculate the angle at which the first minimum occurs for 405nm light, we need to use the equation θ = λ/d, where θ is the angle in degrees, λ is the wavelength of the light, and d is the slit width. Thus, for 405nm light, we have θ = 405nm/2.5um = 162°.

B) To calculate the angle for 740nm light, we can use the same equation, so θ = 740nm/2.5um = 296°. Thus, the first minimum for 740nm light occurs at an angle of 296°.