Question

a pomegranate is thrown from ground level straight up into the air at time with velocity 176 feet per second. its height in feet at seconds is . find the time it hits the ground and the time it reaches its highest point.

Answer 1

176 ft/s / 32 ft/s^2 = 5.5 sec

The pomegranate decelerates at 32 ft/sec^2 and reaches the top in 5.5 s

It will again reach the ground in 2 * 5.5 = 11 sec

S = 1/2 g t^2 = 16 * 5.5^2 = 484 ft where S is the height reached

H = V0 t - 1/2 g t^2 is the height of the pomegranate at time t

Suppose t = 11 sec then

H = 176 * 11 - 16 * 11^2 = 0 its back where it started