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Condense the equation
2log9= log3 - logx

User Pup
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1 Answer

3 votes

Answer:


x=(1)/(27)

Explanation:

Solve for x.

We need to use the quotient property of logarithms.

Quotient Property of Logarithms:
\log _(b) (x)-\log _(b) (y)=\log _(b) ((x)/(y) )

Apply the property to our equation.


\log((3)/(x))=2\log(9)

Simplify the right side by moving the 2 inside the logarithm.


\log((3)/(x))=\log(9^2)

For the equation to be equal, the argument of the logarithms on both sides of the equation must be equal.


(3)/(x)=9^2

Evaluate
9^2.


(3)/(x)=81

Multiply both sides of the equation by x.


(3)/(x)x=81x

Cancel the common factor of x on the left side.


3=81x

Divide both sides by 81.


(3)/(81) =(81x)/(81)


(3)/(81) =x

Simplify the fraction.


x=(1)/(27)

User PGreen
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