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In circle J with the measure of minor arc HK= 58°, find m/HLK. Answer: m/HLK = ??
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In circle J with the measure of minor arc HK= 58°, find m/HLK.

Answer: m/HLK = ??

In circle J with the measure of minor arc HK= 58°, find m/HLK. Answer: m/HLK = ??-example-1
User Almudhafar
by
8.5k points

1 Answer

4 votes

Answer:

∠ HLK = 29°

Explanation:

the measure of the inscribed angle HLK is half the measure of its intercepted arc, that is

∠ HLK =
(1)/(2) × HB =
(1)/(2) × 58°= 29°

User Yannick K
by
8.5k points
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