Question

Two forces that are F1 =15N (east) and F2 = 7N (west) act on a body in a frictionless floor. The displacement of the body is 6 m, what is the work done by forces on the body?​

Answer 1

The net force acting on the body is F1 - F2 = 15 N - 7 N = 8 N (east). Since the displacement of the body is 6 m in the same direction as the net force, the work done by the forces on the body is W = Fnet x d = 8 N x 6 m = 48 J (Joules).

Step-by-step explanation:

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