Question

Two forces that are F1 =15N (east) and F2 = 7N (west) act on a body in a frictionless floor. The displacement of the body is 6 m, what is the work done by forces on the body?​

Answer 1

The work done by the forces on the body is -90 J.
This is calculated by multiplying the magnitude of the forces (F1 and F2) by the displacement (6 m):
W = F1 * d + F2 * d = 15N * 6m + 7N * 6m = -90 J.