C3H8(g) + 5 O2(g) ---> 3CO2(g) + 4 H2O(g) What volume of oxygen is required to completely combust 0.452L od propane (C3H8) at STP

asked Mar 24, 2024 99.5k views

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C3H8(g) + 5 O2(g) ---> 3CO2(g) + 4 H2O(g)

What volume of oxygen is required to completely combust 0.452L od propane (C3H8) at STP

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Answer: 1.86 L of oxygen is required to completely combust 0.452 L of propane at STP.

Optimight answered Mar 30, 2024

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