The concentration of the sulfuric acid : 0.499 M
The net ionic equation
2 OH ⁻(aq]+ 2 H ⁺ (aq] → 2 H ₂O (l]
Further explanation
Given
42.68 ml of 0.43 M KOH
18.40 ml of H2SO4
Required
the concentration of the sulfuric acid
the net ionic equation
Solution
Acid-base titration formula
Ma. Va. na = Mb. Vb. nb
Ma, Mb = acid base concentration
Va, Vb = acid base volume
na, nb = acid base valence
Input the value :
a=KOH, b= H2SO4
0.43 x 42.68 x 1 = Mb x 18.40 x 2
Mb = 0.499 M
The net ionic equation
Reaction
2KOH + H2SO4 → K2SO4 + 2H2O
2 K ⁺ (aq]+ 2 OH ⁻ (aq] + 2 H ⁺ (aq] + SO ₄²⁻(aq] → 2 K ⁺ (aq] + SO ₄²⁻(aq] + 2 H ₂ O (l]
canceled the spectator ions :
2 OH ⁻(aq]+ 2 H ⁺ (aq] → 2 H ₂O (l]