Question

The maximum speed v (in meters per second) of a trapeze artist is MTR represented by v = V2gh, where g is the acceleration due to gravity (g ~ 9.8 m/sec?) and h is the height (in meters) of the swing path. Find the height of the swing path for a performer whose maximum speed is 7 meters per second.

Answer 1

The height of the swing path for a performer with a maximum speed of 7 m/s can be calculated using the equation h = v² / (2g). Plugging in the values, the height is approximately 2.27 meters.

Step-by-step explanation:

The maximum speed of a trapeze artist can be calculated using the equation v = √(2gh), where v is the maximum speed, g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the height of the swing path. To find the height of the swing path for a performer with a maximum speed of 7 m/s, we can rearrange the equation as h = v² / (2g). Plugging in the given values, we get h = (7 m/s)² / (2 * 9.8 m/s²) = 2.27 m. Therefore, the height of the swing path for the performer is approximately 2.27 meters.