Question

A 5.0 kg block is placed at the top of frictionless ramp that is inclined so that it makes an angle of 13.5 degrees with the horizontal. The ramp has a length of 2.1 meters. If the block started from rest, how fast will it be moving when it reaches the bottom of the incline?

Answer 1

Step-by-step explanation:

Ramp height:

H = L*sin α = 2.1*sin 13.5° = 2.1*0.2334 ≈ 0.49 m

Acceleration:

a = g*sin α = 9.8*0,2334 ≈ 2.29 m/s²

Speed:

V = √ (2*a*L) = √ (2*2.29*2.1) ≈ 3 m/s

Answer 2

3.101 m/s

Step-by-step explanation:

In this example we used Newton's Second Law and some of the kinematic equations.

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