Question

Select the correct answer. The sum of the digits of a three-digit number is 13. The tens digit, t, is 1 more than the hundreds digit, h. The units digit, u, is 3 more than the sum of the tens and hundreds digits. Which system of equations can be used to find each digit?

Could someone help me understand? im a but confused ​

Answer 1

Using the system of equations we get the values of 3 digit number as:

238

Given:

The sum of the digits of a three-digit number is 13.

The tens digit, t, is 1 more than the hundreds digit, h. The units digit, u, is 3 more than the sum of the tens and hundreds digits.

we are asked to determine each digit of the given number:

we frame the equation as:

tens digit (t) = 1+h

hundreds digit (h) = h

units digit (u) = 3+(t+h)

hence,

h + (1+h) + (3+(t+h)) = 13

open the brackets.

h+1+h+3+(t+h)=13

substitute t value from the above mentioned state.

h+1+h+3+((1+h)+h)=13

h+1+h+3+1+h+h=13

arrange the like terms and add.

4h + 5 = 13

4h = 13-5

4h=8

h = 8/4

h = 2

hence we get the hundreds digit as 2.

now substitute it to get t and u value.

t = 1+h

t = 1+2

t = 3

tens digit = 3

u = 3+(t+h)

u = 3+(3+2)

u = 3+5

u = 8

units digit = 8