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What is an equation of the line that passes through the points (-2, -6)(−2,−6) and (-1, 0)(−1,0)?

2 Answers

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The equation of the line that passes through the points (-2, -6) and (-1, 0) is y = 3x + 6.
User Tapas Talukder
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Step-by-step explanation: An equation of a line can be written in the slope-intercept form y = mx + b, where m is the slope of the line and b is the y-intercept. To find the equation of a line that passes through two given points, we can use the slope-intercept form and find the slope (m) and y-intercept (b) using the two points.

To find the slope (m), we can use the formula: m = (y2 - y1) / (x2 - x1)

Given the points (-2, -6) and (-1, 0), the slope of the line is:

m = (0 - (-6)) / (-1 - (-2)) = 6 / 1 = 6

To find the y-intercept (b) , we can substitute one of the points into the slope-intercept form:

y = mx + b

(-6) = 6(-2) + b

b = -6 - 12 = -18

Now we can use the slope and the y-intercept to write the equation of the line in slope-intercept form:

y = 6x - 18

So the equation of the line that passes through the points (-2, -6) and (-1, 0) is y = 6x - 18

User Yuriy Nazarov
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