78.4k views
5 votes
Quadrilateral ABCD is a rhombus. If mzCDB = 6y° and mZACB = (2y + 10)°, find the value of y.

Quadrilateral ABCD is a rhombus. If mzCDB = 6y° and mZACB = (2y + 10)°, find the value-example-1
User Badmaash
by
8.0k points

1 Answer

7 votes

Answer:
y=10

Explanation:

Note that
\angle ACB \cong \angle ACD because diagonals of a rhombus bisect the angles from which they are drawn.

Now, because
m\angle DEC=90^(\circ) since diagonals of a rhombus are perpendicular, it follows that
m\angle CDB+m\angle ABC=90^(\circ).


6y+2y+10=90\\\\8y+10=90\\\\8y=80\\\\y=10

User Marcel Gruber
by
9.4k points

Related questions

1 answer
4 votes
116k views
1 answer
0 votes
228k views
2 answers
2 votes
70.6k views