Answer:
around 3.7996 g of fluorine.
Step-by-step explanation:
To determine the number of grams in one tube of toothpaste, we would first need to know the molar mass of fluorine and the number of moles of fluorine present in the toothpaste.
The molar mass of fluorine (F) is 18.998 g/mol.
So, we can find the number of moles of F present in the toothpaste using the Avogadro number (1.2x10^24 atoms of F)
1.2x10^24 atoms of F = (1.2x10^24 atoms F)/(6.022x10^23 atoms/mol) = 2 x 10^-1 mol
Now, we can use the molar mass of fluorine to determine the number of grams of fluorine in one tube of toothpaste:
mass of F = molar mass of F * number of moles of F
mass of F = 18.998 g/mol * 2x10^-1 mol = 3.7996 g
So one tube of toothpaste contains around 3.7996 g of fluorine.