Question

2 NaCl + O₂ -> OCI₂ + 2 Na

If she does the reaction with 56.44 grams of O₂, how many grams of Na are created? answer choices, 162.2, 81.10, or 20.28

Answer 1

Answer: 81.10 gram Na

Step-by-step explanation:

You would use stoichiometry to convert from mass of O2 to mass of Na.

`(56.44 g O2)/(1) *(1molO2)/(32 g O2) * (2molNa)/(1molO2) *(22.99gNa)/(1molNa)`

Start with the given mass of O2, then multiply it with a figure that converts the grams of O2 to moles of O2. There are 32 grams of O2 per mole. The grams of O2 cancel out because its both in the denominator and numerator. Next you would look at the coefficients in the balanced equation. We see that there is a 1:2 ratio of moles of O2 to moles of Na. Then we convert moles of Na to grams of Na. There are 22.99 grams of Na per mole. This is where you would finish the equation. Now that all the units have been canceled out, you would multiply everything in the numerator and divide it by the product of everything in the denominator. (56.44*1*2*22.99)/(32*1*1)=81.10.