Question

Use point-slope form to write the equation of a line that passes through the point (1,-3) with slope -5/3

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Answer 1

y=-5/3x-4/3

Explanation:

Point-slope from is y-y1=m(x-x1). y1 is -3 m is -5/3 x1 is 1. It looks like (y-(-3)=-5/3(x-1)). Now a negative times a negative is a positive so it would be (y+3=-5/3(x-1)) Now you must distribute. (y+3=-5/3x+5/3) and subtract 3 (y=-5/3x-4/3)

Hope this helped!

Answer 2

y +3 =
`(-5)/(3)`(x -1)

Explanation:

The point slope form of a line is

y -
`y_(1)` = m( x -
`x_(1)`) The
`y_(1)` and
`x_(1)` come from the point given (1,-3) and the slope is given. You plug it in.

y - -3 =
`(-5)/(3)` ( x -1) y - -3 is the same as y + 3

y + 3 =
`(-5)/(3)`( x -1)