Question

PLEASE HELP

A new cruise ship line has just launched 3 new ships: the Pacific Paradise, the Caribbean Paradise, and the
Mediterranean Paradise. The Caribbean Paradise has 31 more deluxe staterooms than the Pacific Paradise. The
Mediterranean Paradise has 26 fewer deluxe staterooms than twice the number of deluxe staterooms on the Pacific
Paradise Find the number of deluxe staterooms for each of the ships if the total number of deluxe staterooms for the
three ships is 609.
The answers MUST add up to 609

Answer 1

• Pacific Paradise: 151
• Caribbean Paradise: 182
• Mediterranean Paradise: 276

Explanation:

Given three cruise ships, which we can reference as P, C, and M, and relations between the numbers of deluxe staterooms in each, you want to know the numbers on each ship. C has 31 more than P; M has 26 fewer than twice the number on P; the total on all ships is 609.

Setup

The relations can be described by the equations ...

P + C + M = 609

-P +C = 31

2P -M = 26

Solution

The attachment shows a matrix solution:

(P, C, M) = (151, 182, 276)

Substitution

We can use the last two equations to write expressions for C and M to substitute into the first equation:

C = 31 +P

M = 2P -26

Then ...

P + (31 +P) +(2P -26) = 609 . . . . substitute for C and M

4P = 604 . . . . . . subtract 5

P = 151 . . . . . . . divide by 4

Then the other values are ...

C = 31 +151 = 182

M = 2(151) -26 = 276

The numbers of deluxe staterooms on each ship are ...

• Pacific Paradise: 151
• Caribbean Paradise: 182
• Mediterranean Paradise: 276