Question

Consider the combustion reaction of acetylene (C₂H₂):

2C₂H₂ +502 --> 4CO₂ + 2H₂O
Use the periodic table to determine how many grams of oxygen would be required to react completely
with 859.0 g C₂H₂?
O 423.0 g 0₂
O
832.0 g 0₂
O
1,750. g 0₂
O2,640. g 0₂

Answer 1

Answer: 2638 g O₂ (closest answer is 2640 g O₂)

Step-by-step explanation:

Use the equation to find the number of grams of O₂ that will react with 959.0 g C₂H₂.

Step 1: Determine if the equation is balanced.

There are 4 carbon atoms on both sides of the equation.

There are 4 hydrogen atoms on both sides of the equation.

There are 10 oxygen atoms on both sides of the equation.

The equation is balanced.

Step 2: Determine molar mass of C₂H₂.

C: 2 x 12.01 g = 24.02 g

H: 2 x 1.01 g = 2.02 g

Total grams = 26.04 g

Step 3: Set up the conversion factors using grams of C₂H₂ from the problem, the molar mass of C₂H₂, and the ratio of C₂H₂ and O₂.

859.0 g C₂H₂ x (1 mol C₂H₂/26.04 g C₂H₂) x (5 mol O₂/2 mol C₂H₂) x (32.00 g O₂/ 1 mol O₂) = 137,400 g/52.08 = 2638 g