Question

2m-16=1/3(2m+4)

Please explain

Answer 1

Explanation:

Combine multiplied terms into a single fraction

2m-16= 1/3( 2m+4)

2m-16= 1(2m+4)/3

Multiply by 1

2m-16=1(2m+4)/3

2m-16=2m+4/3

Add 16 to both sides

2m-16=2m+4/3

2m-16+16=2m+4/3

2m-16+16-2m+4/3+16

Multiply all terms by the same value to eliminate fraction denominators

2m= 2m+52/3

3x2m=3x2m+52/3

Cancel multiplied terms that are in the denominator

3x2m=3x2m=52/3

3x2m=2m+52

Multiply the numbers

3x2m=2m+52

6m=2m+52

Subtract 2m from both sides

6m=2m+52

6m-2m=2m+52-2m

Combine like terms

6m-2=2m+52-2m

4m=2m+52-2m

combine like terms

4m=2m+52=2m

4m=52

Divide both sides by the same factor

4m=52

4m/4=52/4

Cancel terms that are in both the numerator and denominator

4m/4=52/4

m=52/4

Divide the numbers

m=52/4

m=13

That's how you get 13

hope this helped :)

Answer 2

`2m-16=(1)/(3) (2m+4)`

Distribute:

`2m-16=((1)/(3) )(2m)+((1)/(3) )(4)`

`2m-16=(2)/(3) m+(4)/(3)`

Subtract
`(2)/(3) m` from both sides:

`2m-16-(2)/(3) m=(2)/(3) m+(4)/(3) -(2)/(3) m`

`(4)/(3)m-16=(4)/(3)`

Add 16 to both sides:

`(4)/(3) m-16+16=(4)/(3) +16`

`(4)/(3) m=(52)/(3)`

Multiply both sides by
`(3)/(4)`:

`(3)/(4) *((4)/(3) m)=(3)/(4) *((52)/(3) )`

`\boxed{m = 13}`