Solve for x:- \mathrm{4x-(9-3x)=8x-1}

Question

Solve for x:-

`\mathrm{4x-(9-3x)=8x-1}`

Answer 1

x = -8

Explanation:

Solve for x:

-(9 - 3 x) + 4 x = 8 x - 1

-(-3 x + 9) = 3 x - 9:

(3 x - 9) + 4 x = 8 x - 1

Grouping like terms, 4 x + 3 x - 9 = (4 x + 3 x) - 9:

((4 x + 3 x) - 9) = 8 x - 1

4 x + 3 x = 7 x:

7 x - 9 = 8 x - 1

Subtract 8 x from both sides:

(7 x - 8 x) - 9 = (8 x - 8 x) - 1

7 x - 8 x = -x:

-x - 9 = (8 x - 8 x) - 1

8 x - 8 x = 0:

-x - 9 = -1

Add 9 to both sides:

(9 - 9) - x = 9 - 1

9 - 9 = 0:

-x = 9 - 1

9 - 1 = 8:

-x = 8

Multiply both sides of -x = 8 by -1:

(-x)/(-1) = -8

(-1)/(-1) = 1:

Answer: x = -8

Answer 2

`\sf \: x = - 8`

Explanation:

Now we have to,

→ Find the required value of x.

The equation is,

→ 4x - (9 - 3x) = 8x - 1

Then the value of x will be,

→ 4x - (9 - 3x) = 8x - 1

→ 4x - 9 + 3x = 8x - 1

→ 7x - 9 = 8x - 1

→ 7x - 8x = -1 + 9

→ -x = 8

→ [ x = -8 ]

Hence, the value of x is -8.