Question

If y = x^2 -1/x find dy/dx

Answer 1

`(dy)/(dx) = 2x + (1)/(x^(2))`

Explanation:

`y = ax^(n)` where a is a constant

`(dy)/(dx) = anx^(n-1)`

Applying the above mentioned concept:

`y = x^(2) -1x^(-1)`

`(dy)/(dx) = 2x^(2-1) - 1 [(-1)(x^(-1-1))]`

`= 2x +1(x^(-2) )`

`(dy)/(dx) = 2x +(1)/(x^(2) )`