Question

2 NaCl + O₂ -> OCI₂ + 2 Na

If she does the reaction with 56.44 grams of O₂, how many grams of Na are
created?

Answer 1

Step-by-step explanation:

The balanced equation for the reaction is 2 NaCl + O2 -> 2 Na + 2 ClO.

Since the number of moles of Na that are produced is directly proportional to the number of moles of O2 used, we can use the ideal gas law PV = nRT to determine the number of moles of O2 used.

The number of moles of O2 used is 56.44 / 32 = 1.77 moles.

Since the number of moles of Na produced is equal to the number of moles of O2 used, the number of moles of Na produced is also 1.77.

To find the number of grams of Na produced, we can multiply the number of moles of Na produced by the molar mass of Na (22.99 g/mol)

So the number of grams of Na produced is 1.77 moles * 22.99 g/mol = 40.7 grams.