Question

A rectangle with an area of 432ft has a length that is the 6 more feet than it’s width. Find the width and length of the rectangle?

Answer 1

width of the rectangle is 12 ft and the length is 18 ft.

Explanation:

Let's call the width of the rectangle "w" and the length "l". From the problem, we know that:

Area = 432 ft^2

l = w + 6 ft

We also know that the area of a rectangle is found by multiplying the width by the length, so:

432 = w * (w + 6)

We can simplify this equation by multiplying out the right side:

432 = w^2 + 6w

Now we have a quadratic equation in one variable, we can solve for w by either factoring, completing the square or using the quadratic formula.

432 = w^2 + 6w

432 = w(w + 6)

w(w+6)=432

w=12

Now that we know the width is 12 we can use the second equation to find the length:

l = w + 6 = 12 + 6 = 18

So the width of the rectangle is 12 ft and the length is 18 ft.