Step-by-step explanation:
To calculate the percent composition of a 35.4 g piece of silver (Ag) that combines completely with 22.3 g of CO to form AgCL, we need to know the molar mass of Ag and CO.
Ag = 107.87 g/mol
CO = 28.01 g/mol
The balanced equation for the reaction is:
Ag + CO → AgCL
So, we have 35.4 g of Ag and 22.3 g of CO reacting to form AgCL.
First, we need to calculate the moles of Ag and CO.
moles of Ag = 35.4 g / 107.87 g/mol = 0.327 moles
moles of CO = 22.3 g / 28.01 g/mol = 0.796 moles
Now, we can use the moles of each component to find the percent composition of Ag and CO in AgCL.
% of Ag = (moles of Ag / (moles of Ag + moles of CO)) x 100% = (0.327 / (0.327 + 0.796)) x 100% = 29.3%
% of CO = (moles of CO / (moles of Ag + moles of CO)) x 100% = (0.796 / (0.327 + 0.796)) x 100% = 70.7%
Therefore, the percent composition of Ag in AgCL is 29.3% and the percent composition of CO in AgCL is 70.7%.