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If 1.82 mol of ZnS is heated in the presence of 3.94 mol of O2, which is the limiting reactant?

User Dony
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Answer:

In Explanation

Step-by-step explanation:

In a chemical reaction, the limiting reactant is the reactant that is completely consumed before any of the other reactants are used up. The amount of product that can be formed is determined by the limiting reactant, and the amount of the excess reactant left over after the reaction can be calculated.

To determine which reactant is the limiting reactant, we need to compare the stoichiometry of the reaction, which is the ratio of the reactants and products in a balanced equation.

The balanced equation for the reaction between ZnS and O2 is :

ZnS + O2 → ZnO + SO2

From the balanced equation, we can see that 1 mole of ZnS reacts with 1 mole of O2 to form 1 mole of ZnO and 1 mole of SO2.

Now we can compare the amount of ZnS and O2 that we have with the stoichiometry of the reaction.

1.82 moles of ZnS is enough to react with 1.82 moles of O2

But we have 3.94 moles of O2, which is more than enough to react with the 1.82 moles of ZnS

Therefore ZnS is the limiting reactant and O2 is the excess reactant.

User Neeraj Bhadani
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