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What is the equation of a circle with a radius of 4 and a center located at (2,3)

1 Answer

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Answer:

x² + y² - 4x - 6y - 3 = 0

Explanation:

Formula for equation of circle when the radius r and centre (a,b) is given:

(x-a)² + (y-b)² = r²

(x-2)² + (y-3)² = 4²

Expanding the brackets;

x² - 4x + 4 + y² - 6x + 9 = 16

x² + y² - 4x - 6x + 4 + 9 = 16

x² + y² - 4x - 6x + 13 = 16

x² + y² - 4x - 6x + 13 - 16 = 0

x² + y² - 4x - 6x - 3 = 0 Ans.

User Dom Vinyard
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