18.4k views
3 votes
3x - x^{2} + 2 < 0
solve this quadratic inequality graphically

User Nima K
by
7.7k points

1 Answer

4 votes

(−∞,−3) (2,+∞)

Step-by-step explanation:

graph the parabola

y=−x2−x+6

and consider which parts are less than zero, that is below the x-axis finding the x and y intercepts

let x = 0, in the equation for y-intercept

let y = 0, in the equation for x-intercepts

x=0→ y=6←

y-intercept

y=0→ −x2−x+6=0

multiply through by - 1

⇒ x2+x−6=0

the factors which multiply to give - 6 and sum to + 1 are + 3 and - 2

⇒(x+3)(x−2)=0

⇒x=−3 or x=2←

x-intercepts

obtaining the shape of the parabola

if a>0

then minimum if a < 0

then maximum for y =−x2−x+6xa<0

we can now graph the parabola

graph{-x^2-x+6 [-10, 10, -5, 5]}

x<−3 or x>2

are the parts below the x-axis

in interval notation

(−∞,−3)∪(2,+∞)

User GhostCKY
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories