Question

100 points

For the oxidation of glucose (C₆H₁₂O₆ + 6O₂→6H₂O + 6CO₂), how many liters of carbon dioxide gas(CO₂) will be produced when 950 g of glucose(C₆H₁₂O₆) is oxidized completely?

Molar Masses:
C₆H₁₂O₆ = 180.2 g/mol

Question 1 options:

480g
571g
709g
960g

question 2
From Question 1, you calculated the theoretical yield of CO₂ in liters.

Use that value to calculate the percent yield if 250L of CO₂ are collected for the actual yield.

Percent Yield = actual yield/theoretical yield x 100%

Question 2 options:

79%
72%
25%
35%

Answer 1

709g of CO2 will be produced when 950g of glucose is oxidized completely.

The percent yield would be 35%. (250L / 709g) * 100 = 35%.