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What is the equation of the line that

passes through the point (3, -4) and has
a slope of -5/3?

1 Answer

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Answer:

y +4 = -5/3(x -3) or y = -5/3x +1

Explanation:

You want the equation of the line with slope -5/3 through point (3, -4).

Point-slope equation

The point-slope equation for a line is ...

y -k = m(x -h) . . . . . . line with slope m through point (h, k)

For the given slope and point, your equation is ...

y -(-4) = -5/3(x -3)

y +4 = -5/3(x -3) . . . . . . point-slope equation of the line

Slope-intercept equation

This equation can be rearranged to slope-intercept form

y = -5/3x +5 -4 . . . . . eliminate parentheses, subtract 4

y = -5/3x +1 . . . . . . . collect terms

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Additional comment

The equation can also be rearranged to standard form:

5x +3y = 3

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User Ed Stephenson
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